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Fischer Random Chess: Manual Procedure for Generating Piece Plac. Manual Procedure for Generating Piece Placements.[All Comments] [Add Comment or Rating]
Edward Northam wrote on 2006-09-06 UTC
It is possible  to get by with fewer drawings if Mr Baljeu's suggeston of
using marked pawns if followed.  The pawns should carry the labels 1...8.

At the first drawing, the numbers are associated with piece labels
according to the piece setup in standard chess.  ie. 1,8=R, 2,7=N, 3,6=B,
4=Q, 5=K.  The white pieces should be put on the board, and, if the
Bishops are on same colored squares, the pawns should be put back in the
bag, and  one should be drawn out.  A number in the range 1...4
that the a-side Bishop should trade places with the appropriate piece on
the opposite colored square.  A number in the range 5...8 should be
diminished by 4, and the h-side Bishop should trade places with the
appropriate piece on the opposite colored square. This idea, a randomly
chosen Bishop should move to a randomly chosen square of the opposite
color, is due to David Wheeler.

The same end could be achieved with 8 cards marked, on one side, with the
numbers 1 through 8.

Reinhard Scharnagl wrote on 2005-10-11 UTC
There is of course a numbering scheme for Chess960 (Fischer Random Chess).
I invented it some years ago, and it is widely accepted. For details see
e.g. in my (German) book on Chess960 or see at the two page
document I gave (first page with table) to the Chess Tigers .

With best regards, Reinhard Scharnagl.

Alan Baljeu wrote on 2005-05-13 UTC
Here's a fair way of shuffling the pieces.  All 960 positions are equally
probable, and no extra equipment is needed.  It works by splitting the
placement into two phases for dark and light squares.

1. Randomly shuffle the 6 pieces not including the Bishops.  Divide these
pieces into two groups of 3 each.
2. Take the first 3 pieces and one bishop.  Shuffle these 4 pieces. 
them on a1, c1, e1, and g1.
3. Take the remaining pieces and 1 bishop, and randomly shuffle them. 
Place these pieces on b1, d1, f1, and h1.
4. Correct the king position by swapping with a rook if needed.

Here's the math: 
The first shuffle yields 6-choose-3 or 6*5*4/3/2/1 ways to divide the
The second shuffle yields 4*3*2 permutations of 4 pieces.
The third shuffle yields  4*3*2 permutations of 4 pieces.
Divide by 2 because the knights are the same.  
Divide by 6 because of the king/rook unshuffle.
End result = 5*4*4*4*3 = 960 positions.

To make the shuffle totally fair, label the bottom of your eight pawns
RRRBBNNQ and shuffle them instead of your pieces.

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