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Spartan Skaki. Missing description (9x9, Cells: 81) [All Comments] [Add Comment or Rating]
💡📝Larry Smith wrote on 2008-05-24 UTC
Note the title 'Spartan'.

The rules are simple, the play is complex.

George Duke wrote on 2008-05-20 UTC
Is this a CV? Only one piece-type, stones. No, two, the marked one is King. No problem, CV it is, not Go variant. Or if it is Go variant, where are the other hundreds of Go variants by just royalizing one or two Stones and then diversifying a few, or many, pieces out of some of the others? Here ''all stones move the same''; hey we can do better or more than that in this uncluttered field.

💡📝Larry Smith wrote on 2007-12-15 UTC
I've posted an implementation to Zillions which should answer all your questions.

Pushing an opponent's stone involves only the opponent stone and to the next vacant point. The friendly stone does not move.

Leaping over friendly stones involves only friendly stones and to the first vacant point.

Capture is by replacement.

Peter Aronson wrote on 2007-12-14 UTC
This looks interesting, Larry, but I have a few questions:
2) Push an opposing stone located adjacent right or left orthogonal to the next right or left orthogonal vacant point,
Are pushes limited to one space, or do they go until the next vacant space? IE, if you have a row ---xxo--- is a push by o such that results in --xxo---- legal? Actually, now I think about, does a push cause the pushing piece to move? Would a push in this situation, ---xo---- result in --xo----- or --x-o----?

3) Leap over any number of adjacent friendly stones forward, right or left orthogonal to a vacant point.
Does the leap only pass over friendly stones, or can it (after passing over friendly stones) pass over vacant spaces as well? IE, starting with ---ooo--- is o--oo---- possible, or only leaps like --ooo----? (I assume the latter, but the language is not completely clear.)

4) Capture an opposing stone on an adjacent forward diagonal point.
Is capture by replacement?

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